Documents / Report

Defense Intelligence Reference Document Negative Mass Propulsion

Defense Intelligence Agency · 43 pages · text from the file's own layer

This Defense Intelligence Reference Document from the Defense Intelligence Agency is dated 3 January 2011. It was produced under the Advanced Aerospace Weapon System Applications (AAWSA) Program as part of a series of advanced technology reports. The report asks whether negative mass exists and whether it could be used for propulsion. It concludes that one route might be an ultra-light form of matter that could have gathered at the Moon's center. Reaching it would take a tunnel dug with thermonuclear shape charges.

  • p. 3 UNCLASSIFIED/ /F8A 8FFIGl1l1k WI>& Qtlk':C Contents 1. Introduction ................................................................................................. 2 2. The Theory by Bondi ...................................................................................... 4…
  • p. 9 …partial differential equations ( K = 8;r y / c 4 ) given by ' 'o 2, 1 ,_,,-, 2 2…
  • p. 10 …merry-go-round": mv F=mg+-xG. C (11) If g is the gravitational acceleration by…
  • p. 12 UNCLASSIFIED/ /F81il 8fFllil.t.k WE&i Si'llk>C In one further step one should…
  • p. 17 …velocity of circular motion with f',.(J} ➔ c): + = m r;.rm =m+rc ( 41) Comparing (40…
  • p. 18 …Newton's constant, h Planck's constant, c the velocity of light): 14 UNCLASSIFIED//r;Oll…
  • p. 19 …But since & = r1, and because ml'rl'c = h, one obtains Heisenberg's uncertainty relation .6…
  • p. 20 …leads to a velocity fluctuation ~ a,,t,, = c with a displacement of the particle equal to…
  • p. 23 …l!IP'P'll!lllile lal!i! i;n11e~r transforming (59) into c-~1-' v…
  • p. 24 …and fro directions given by ✓ 2 2 • 'c_ =c -v Slll-1// -VCOSlf/ (67) with the…
  • p. 25 …y(1R-1'.,)=d/c y(t,;-tR)=d/c (70) where dis the distance between…
  • p. 26 …The impossibility is expressed in the Lorentz transformations themselves, containing the scalar c 2 rather than…
  • p. 27 …C Of C (79) (80) (81) By making a gauge transformation of the Hamilton operator in…
  • p. 28 …dt Gt C Complete analogy between (81) and (83) is established if one sets m • =--v…
  • p. 29 …1,1lii s,11.~r where A av E = -+ c&xr-w x(wxr) a, -H…
  • p. 30 …the Lorentz gauge) 4 il , --+divA =0 C Ct With the gauge transformation for ct> and…
  • p. 31 …v · ds c- . ~ 2 2;rv b(f) = 20Jrrr -,- c the same as predicted by quantum…
  • p. 32 …For H = 104 G, this would mean that vmax 2 c for R > 0.3 cm…
UNCLASSIFIED//FIHl 8FFHil.t.k Wfili IH.k\f
-H
r= =10cm,, .
The assumption that SU2 is the fundamental group means that nature works like a
computer with a binary number system. Since SU2 is isomorphic to 503, the rotation
group in R3, this explains why natural space is three-dimensional.
The Planck's aether conjecture is the assumption that the vacuum of space is densely
filled with an equal number of positive and negative Planck mass particles, with each
Planck length volume on the average occupied by one Planck mass, with the Planck
mass particles interacting with each other by the Planck force over a Planck length, and
with Planck mass particles of equal sign repelling and those of opposite sign attracting
each other. The particular choice made for the sign of the Planck force is the only one
that keeps the Planck aether stable. While Newton's action-reaction remains valid for
the interaction of equal Planck mass particles, it is violated for the interaction of a
positive with a negative Planck mass particle, even though globally the total linear
momentum of the Planck mass plasma is conserved, with the recoil absorbed by the
Planck aether as a whole.
It is the local violation of Newton's action-reaction which leads to quantum mechanics
at the most fundamental level, as can be seen as follows: Under the Planck
force Fl' =m 1,c2 I r1,, the velocity fluctuation of a Planck mass particle interacting with a
Planck mass particle of opposite sign is .6.v = ( F1, /ml') ti' = ( c 2 / rP) ( r" / c) = c , and hence
yields the momentum fluctuation .6.p = ml'c. But since &] = r1, and because ml'rl'c = h,
one obtains Heisenberg's uncertainty relation .6.p.6.q = h for a Planck-mass particle.
Accordingly, the quantum fluctuations are explained by the interaction with hidden
negative masses, with energy borrowed from the sea of hidden negative masses.
15
UNCLASSIFIED/ ,'f811. 8ffl81,t.k l.llili liUlklC

Not linked to a story yet.

About this file

Report, from the dia collection. The PDF is mirrored here; the original link is under it. 43 pages are in the text index: search them above, or from the library's search.