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Defense Intelligence Reference Document Negative Mass Propulsion

Defense Intelligence Agency · 43 pages · text from the file's own layer

This Defense Intelligence Reference Document from the Defense Intelligence Agency is dated 3 January 2011. It was produced under the Advanced Aerospace Weapon System Applications (AAWSA) Program as part of a series of advanced technology reports. The report asks whether negative mass exists and whether it could be used for propulsion. It concludes that one route might be an ultra-light form of matter that could have gathered at the Moon's center. Reaching it would take a tunnel dug with thermonuclear shape charges.

  • p. 15 …The spin is definitely not an intrinsic rotational motion of a finite size particle, as older…
  • p. 17 UNCLASSIFIED//FIHl 8FFHil.t.k Wfili IH.k\f in which the luminal rotational motion emerges…
  • p. 19 …Since SU2 is isomorphic to 503, the rotation group in R3, this explains why natural space…
  • p. 29 …Applied to a rotating reference system one has - I z f (87) (88) (89) (90) (91…
  • p. 31 …According to (93), one has for the gravitational vector potential in a rotating frame of reference…
  • p. 32 …If this would be same aether velocity felt on a rotating platform, it would lead to…
  • p. 33 …The corotating configuration is realized on a rotating platform, where it leads to the Sagnac and…
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3. Hund's Nonlinear Newtonian Theory of Gravity
As explained by Hund [3], already Newton's theory of gravity, in conjunction with the
postulates of special relativity, leads to a nonlinear theory of gravity. With this model
theory of gravity the nonlinearity of the gravitational field can be much better explained
than with Einstein's theory.
Hund begins with the force F acting on a mass m in a "merry-go-round":
mv
F=mg+-xG.
C
(11)
If g is the gravitational acceleration by real masses with the density p, one has in
Newton's theory
divg =-4nyp. (12)
In the merry-go-round g has a vertical component from the earth's gravitational field,
but also a radial component by the radial centrifugal acceleration which is not source-
free. With lxl = (1/r, where OJ= 2tr/T, with T the time of revolution, and r the radial
distance from the center of the merry-go-round, one has
divg = 2a/ _ (13)
Comparing (13) with (12) one sees that the centrifugal force corresponds to a
gravitational repulsion of a homogeneous mass density
(14)
For a typical "merry-go-round" one has T = 10 sec, and hence, w = 0.6s 1
• For this
example one obtains from (14), f.L=-106
glen/, taken as an absolute value about
equal to the mass density of a white dwarf.
6
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Report, from the dia collection. The PDF is mirrored here; the original link is under it. 43 pages are in the text index: search them above, or from the library's search.